Recent content by jlee888

So far what I did was PEtop= KE bottom mgh=.5mv^2 gh=.5v^2 (9.81)h=(0.5)v^2 then at the point where the boy just barely stays on the ice mound, I used the equation Fn= Fw-Fc, which would be 0 at that point 0=mg-(mv^2/r) mg=(mv^2/r) g=v^2/r gr=v^2 (9.81)(13.8)=v^2 v^2= 135.378...