Recent content by JMaria

  1. J

    Capacitor Energy with a Dielectric

    So should I square the value first then convert it to meters? Am I plugging this in right? For part A: [(1/2)(8.85*10^-12)(3)(.225)]/(2*5*10^-3)
  2. J

    Capacitor Energy with a Dielectric

    Homework Statement A dielectric-filled parallel-plate capacitor has plate area A = 15.0cm2 , plate separation d = 5.00mm and dielectric constant k = 3.00. The capacitor is connected to a battery that creates a constant voltage V = 5.00V . Throughout the problem, use ϵ0 = 8.85×10−12C2/N⋅m2 ...