Recent content by jmed

  1. J

    What is the relationship between lighthouse location and beam rotation speed?

    A lighthouse is located off shore one mile from the nearest point P, on a straight coastline. The light makes 4 revolutions per minute. How fast is the beam of light moving along the shoreline when it is 2 miles from point P? lighthouse is one mile from point P...trying to find how fast beam of...
  2. J

    What is the relationship between lighthouse location and beam rotation speed?

    ok, so the circumference is 2 pi and that divided by 4 is pi/2. So I'm still confused on how to find how fast the beam is moving when 2 miles from point P.? The distance from the lighthouse to the point 2 miles from P is Sqrt of 5. ...
  3. J

    What is the relationship between lighthouse location and beam rotation speed?

    Any help?! I'm still unsure where to go with this?
  4. J

    What is the relationship between lighthouse location and beam rotation speed?

    what formula is going to be used to find the rate of the light beam?
  5. J

    What is the relationship between lighthouse location and beam rotation speed?

    so the hypotnuse is the unknown (d). the distance up the shoreline is 2. the distance from P to the light house is 1. How is the tan of theta d/1? wouldn't it be 2/d?
  6. J

    What is the relationship between lighthouse location and beam rotation speed?

    Homework Statement A lighthouse is located off shore one mile from the nearest point P, on a straight coastline. The light makes 4 revolutions per minute. How fast is the beam of light moving along the shoreline when it is 2 miles from point P? Homework Equations The Attempt at a...
  7. J

    Calculating the Speed of Airplane Above an Observer

    so then x = 4 after 30 seconds and r is then = to 5. This equates to (480*4)/5 = dr/dt. Which equals 384 mph?
  8. J

    Calculating the Speed of Airplane Above an Observer

    x = distance plane has traveled...dx/dt is equal to rate at which plane is traveling...r is distance from observer to plane 30 sec. later. dr/dt is equal to rate of distance from observer to airplane 30 sec later. dx/dt would equal 480mph. dr/dt is what I am trying to find.
  9. J

    Calculating the Speed of Airplane Above an Observer

    I still need a rate tho. I have x*dx/dt= r*dr/dt. I am not sure how to use the 480mph and the 30sec to find a rate. Is dx/dt = 30sec?
  10. J

    Calculating the Speed of Airplane Above an Observer

    a^2 + b^2 = c^2?? but then how do I differentiate?
  11. J

    Calculating the Speed of Airplane Above an Observer

    It is 3 miles. I am confused on what to use? I thought 45-45-90 because I calculated x to be 4 which would make the hypotnuse 5...?
  12. J

    Calculating the Speed of Airplane Above an Observer

    Ok so it is a 45-45-90? Then I can use law of sine? Also, the altitude is 3km. So if I use law of sine, I get d = 4.2426...i'm not sure how I can differentiate from here tho...
  13. J

    Calculating the Speed of Airplane Above an Observer

    Would law of cosine come into play? d^2 = 1^2 + x^2 - 2*1*x cos90. Then from here differentiate?
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