Recent content by Joe Schmoe

OK, my bad. I am just unsure at how to rearrange d/340=d/1400+0.95 to isolate d. Any ideas?

So would the answer be 690m?

You mean like this: 340=d/(d/1400)+0.95

no, sorry, I mean: d/340=d/1400+0.95

Then, t2=t1+0.95 so: d/1400=d/340+0.95

OK, so t1 (water)= d/1400 t2 (air)= d/340

Well, I obviously know that d=t×v. This would mean that in the air the sound travels 323 m (d= 0.95×340). The problem is that isn't the total distance, there remains an additional distance that I can't figure out. If I sub in the time value into an equation with the sound velocity in water...

Homework Statement David is swimming when he hears a beaver sap the water with its tail, first through the water (v= 1400 meters/second) and then 0.95 seconds later (after the sound reaches him through the water) through the air (v= 340 meters/second). Homework Equations Find the...