Recent content by joek856

the keff for the adjoint flux will be the same as for the normal flux, 1 in a critical reactor. I am unfamiliar with the power method for solving these equations, but if you can solve the equations for regular flux, the same methodology will apply for the equations with the adjoint operators in...

It is easier to think of in terms of matrix operators. The equation can be rewritten in terms of a multiplication operator, M, and a fission operator F where: M = \nabla D \nabla + \Sigma_a F = \nu \Sigma_f \Chi These operators can then be written in matrix form for a two-group...