Recent content by joeyjoey

ok. thank you for the help!

this is how the question looks

I use WebAssign, which has marked it as incorrect. I do not know the answer, but I feel like what I did here is probably right.

I already how to properly set it up and execute the equation with natural log etc. 2/3q0 = q0e^(t/RC) 2/3 = e^(-t/tau) ln(2/3) = -t/tau t = -ln(2/3)tauThe problem should be trivial; however, -ln(2/3)tau is apparently incorrect. So is ln(3/2). Is there something I am missing?