Recent content by JohnSmith236

Oh yes of course, thank you very much Chester I really appreciate the fact that you pointing that out to me I completely left out that equation by mistake.

So therefore, the power would be equal to -W+˙m(hin−hout+gzin−gzout))

That is what I am trying to figure out.

Yes, at the bottom of the pipe where the water exits it is static, meaning the change in height is 2m-0m is that right? p1 - p2 = γ (h2 - h1) where γ is the specific weight (N/m3) which is γ = ρ g, γ = 1000*9.81=9810 Not sure if this is the equation i should've used need help on this part of the...

Thank you for your response. Yes, it is static however I am not sure what the formula is for the pressure head (h) and whether the formula I have used is correct since I haven't used the diameter given. Furthermore, how would I introduce the effects of friction into the problem?

Homework Statement A pump is used to move water through a pipe of diameter 150mm, Figure below. The water has a temperature of 20 Celsius and an absolute pressure of 100KPa. The pump moves the water up a vertical distance of 2m and the water exists at atmospheric pressure. Q1) Assuming the...