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Min Steel Wire Diam for 390N: 0.296mm
E=Stress/Strain E=(force/area)/(Change in length/original length) E*(change in length/original length)= force/area area=force/(E*(change in length/original length)) PiR^2=(390N)/((2.0*10^11)/(0.0021m/1.92m)) R^2=((390N)/((2.0*10^11)/(0.0021m/1.92m)))/Pi...- johntuan2009
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- Forum: Introductory Physics Homework Help
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Min Steel Wire Diam for 390N: 0.296mm
A steel wire of length 1.92 m with circular cross section must stretch no more than 0.210 cm when a tensile (stretching) force of 390 N is applied to each end of the wire. What minimum diameter is required for the wire? Express your answer in millimeters. Take Young's modulus for steel to be Y...- johntuan2009
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- Stress Wire
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- Forum: Introductory Physics Homework Help