Recent content by joker2413

read what you said a few times but don't get some of it... but for the problem would it be X = 0 and the principal values are X = \pi/2 and what I am doing right now and for the past 5 days is reviewing trigonometry i just have a little trouble with some of it.

yeah i did mean X= cos-1(1) new here and didnt see the tags... sorry... calc says cos-1(1) = 0 but i kind of remember cos x = 90º which one is a principal value?

ohhh, i get it now.. must of overlooked it... sorry.:blushing:

for this problem i only looked the last 3 digits of the last 2 rows 192. 210. 192 18. ? 18 i noticed 192 + 18 = 210 and then it goes back to 192 so i thought maybe that 18 + 18 = 36? only thing i could see a pattern in the last 2 rows.

that would work to i just wasnt sure if there was any special rules with cos being multiplied.. so the final answer is cos x= 1? or would it be like... cos-1(cosx) = cos-1 X = cos-1 or do i have to do something else?

@_@ lol i must be tired... thanks 3cosX - 1 = 2 3cosX -3 = 0 but i still don't have any idea of what to do from there.

1.Solve the following for the principal values of the indicated variable. 2. 3cos x-1=2 3. 3cosx - 1 = 2 3cosx+1=0 im not sure what to do from here, I would ask a teacher or a tutor but it is summer work for a calculus course and i forgot what to do. I have looked in a...