Recent content by joseph9496

  1. J

    Integration Help: dx/(5-4x-(x^2))^(5/2)

    OH YEAH! i never thought of that! thanks a lot!
  2. J

    Integration Help: dx/(5-4x-(x^2))^(5/2)

    Homework Statement Hi everyone im stuck with the following integration.. Homework Equations integral of dx/(5-4x-(x^2))^(5/2) The Attempt at a Solution can anyone help me? thanks
  3. J

    Undergrad Can we get a negative value for areas of surfaces of revolution?

    yea..and after i do anti-derivative i got π [ (1/9)y^3 - (2/6)y^2 -y ] which gives me a -16/9... i just dun understand how come my answer is negative.. btw thanks for helping!
  4. J

    Undergrad Can we get a negative value for areas of surfaces of revolution?

    Yes i got to that part too but what happen to the radius (x)? cuz after i multiply the radius with the dS and subsitute value 3 and 1 into y-value i got -16/9..
  5. J

    Undergrad Can we get a negative value for areas of surfaces of revolution?

    the question is.. Find the areas of the surfaces generated by revolvin the curves about the indicated axes. x = (1/3)y^(3/2) - y^(1/2), 1≦y≦3; revolved about y-axis so i use the general formula "S = Integral 2π (radius)(dS)" and the radiu in this case is x which is (1/3)y^(3/2) -...
    • joseph9496
    • Thread
    • Areas Negative Revolution Surfaces Value
    • Replies: 4
    • Forum: Calculus