Recent content by Josh chips

Here is how I have done it For the second stone we have -220 =ut -1/2at^2 -220 =8u -313.6 This gives u as 11.7 m/s Kindly confirm if this is correct

At t=0 , we have the height from which it was thrown

I have taken up as +ve and down as -ve since the first stone was dropped and the second stone was thrown upwards

since the question states they hit the ground at the same time i firs find the time they hit the ground y= ut + 1/2at^2 initial velocity is 0 for the first stone 320= 0 + 4.9t^2 this t= 8 secs since the 2nd stone was thrown 100 m below stone 1 distance from ground is 220m 220 = ut -...

am trying to come up with this drawing in excel

please find attached of what i have done so far

I have the winston equations for the cpc but i am having problems getting the exact shape of a symmetric compound parabolic concentrator in excel Help me with the corrections in terms of the width 2a =10 and half acceptance angle of 30 dg please