Recent content by Jpyhsics

The answer was supposed to be 1124 N.

So I figured out that they were asking for weight and not mass, but thanks everyone.

no...sadly

I was marked wrong by the system.

Initially the hot air balloon is stationary so... FB=Fg ρgV=mg m=1319.2...kg FB=Fg=12941N In the air... a=2d/t^2=0.933...m/s^2 Fnet=FB-Fg (1319-x)(0.93...)=12941-(1319-x)g x=114.6 kg but apparently this is wrong?...

Homework Statement Write the equations of tangent lines to the curve of the implicit function x2+2x+2y2-4y=5 that are normal to the line y=x+122. The attempt at a solution I know that the slope has to be m=-1 I found the derivative using implicit differentiation: dy/dx=(-2x-2)/(4y-4) Now I am...

So I plugged in my values and it was wrong, so I don't really know what else to do.

So does this solution make sense to you?

So I guess my question is which of these two equations do we use in the tension force equations (if either is correct...and if my tension force equations are correct...): a2= -asurface + a1 a2= -2a1

So based on the previous post #43 would that mean that a2= -2a1 If that is the case then it seems as though the acceleration of the surface is not needed as T2 = m2(a2 +g) T1 = m1(a1+μg) Which I would equate the two equations and just for a1 Based on intuition, I don't think we would have...

So if you were to define the right as a negative direction, as indicated in the question would the formulae become: a2= -asurface + a1 ? Does that seem valid?

So does that mean that the acceleration of 1 is half the acceleration of 2? Why would that be so?

I am not ignoring it, I just don't know. As I was taught that the accelerations of both the objects would be the same just in opposite directions, but you have said that is not the case, so I don't know what to assume.

But i think that the positive x direction has been switched in your x direction equations.

That is exactly where I am too!