Recent content by jscushman

It can be fun though! I qualified without studying and only in Physics B with no calculus, so don't worry about the "lack of preparation". In my opinion, it's just luck whether you qualify or not. p.s. Quantumpencil I think I know you :-)

All you need is the fact that the initial energy is going to equal the final energy. The initial energy is the initial potential energies of both Tarzan and Jane. The final energy is the energy that Jane has when she let's go of the vine plus the energy that Tarzan is going to have after he...

There's only one equation that you need here, the basic equation for work: W=Fd You know the value for work, and you know the distance travelled, so finding the force shouldn't be too difficult from there :smile:

The buoyant force is equal to the volume times g times the difference in densities between the two fluids (air and helium, in this case). This means that the mass of the payload will be equal to the volume times the difference in densities. In this case, the density of air at 0˚C is 1.29...

Can you be a bit more descriptive about the pendulum set-up (maybe even draw a picture in Paint?). I'm a bit confused about the whole thing. Thanks!

This situation is impossible. After hitting one wall, it will hit the other wall, and then bounce back in the exact opposite direction as the initial velocity, parallel to the initial velocity. Draw an accurate picture (remember that the angle of incidence will equal the angle of reflection)...

Sorry! I misunderstood your original question. If the ball bounced off the wall, it wasn't an inelastic collision. Here's the updated explanation: Assume that the ball is initially headed towards the wall with a speed v at an angle of 45˚. When it bounces off the wall, it will also be an...

You can't calculate the resultant force, but you can calculate the impulse. The impulse is the change in momentum, and assuming that this ball was traveling at velocity v before the collision and was brought to a (horizontal) stop by the wall, the impulse would be \frac{mv}{\sqrt 2 } (since the...