Recent content by jspen30

  1. J

    More Complex Logarithm and advanced Math Questions

    Thanks for your fast reply Sorry Equation 2 is as follows, as the power symbol didnt work: 2-4a + 2 x 2-2a - 8 = 0 Thanks again
  2. J

    More Complex Logarithm and advanced Math Questions

    Hello, was wondering if anyone could please help me with the following questions as for math I have been given a substitute teacher who is of little help. Any help would be much appreciated, even if its just pointing me in the right direction Equation 1: Log (x-3) = 1 + Log 4 - Log x...
  3. J

    Can Complex Logarithms Challenge Advanced Math Students?

    ok thanks for all your help, and sorry for keeping you up (I live in Australia, and its only 2pm) Cheers Jake
  4. J

    Can Complex Logarithms Challenge Advanced Math Students?

    ok ill re-adjust my notation, thanks again for all the help, you have just taught me in about 5mins what my current substitute couldn't teach my class in 5 lessons. Do you have the knowledge to help me with any of the other equations listed above. If you don't have a lot of spare time or have...
  5. J

    Can Complex Logarithms Challenge Advanced Math Students?

    yes I am very sorry Log 50 - Log 5^2 - Log 2 Log (50 / 5^2 / 2) = Log 1 = 0 is that correct working?
  6. J

    Can Complex Logarithms Challenge Advanced Math Students?

    ok thankyou my current working out is: Log 50 - Log 5^2 - Log 2 Log (50 / 5^2 / 2) =1 Is this correct? Jake
  7. J

    Can Complex Logarithms Challenge Advanced Math Students?

    ok thankyou for telling me this mistake, How would I be able to find the following, showing full working and without using a calculator? y = Log 50 - 2 Log 5 - Log 2 = 2 Log (50/5/2) = 2 Log 5 Thanks again Jake
  8. J

    Can Complex Logarithms Challenge Advanced Math Students?

    it was placed out the front eg y=Log 50 - 2 Log 5 - Log 2 = 2Log (50/5/2) = 2 Log 5 however this is not the final answer, as that is what I am trying to find out, the final answer should be in index form im trying to work out how i would do this equation to end up with an answer in index...
  9. J

    Can Complex Logarithms Challenge Advanced Math Students?

    i believe i used the law Loga xy = loga x + logay However I am not one hundred percent sure as my math teacher is currently away on stress leave (I doubt it was my class), and therefore I may be missing some formulae or equations to compete these questions Thanks again for your quick...
  10. J

    Can Complex Logarithms Challenge Advanced Math Students?

    Hello I am currently studying Math B in high school and am having an extremely hard time with my current assessment. If anyone could please help me with the equations listed below it would be very much appreciated as my current Math teacher is on long service leave, and our substitute is...
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