jspen30
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Hello
I am currently studying Math B in high school and am having an extremely hard time with my current assessment. If anyone could please help me with the equations listed below it would be very much appreciated as my current Math teacher is on long service leave, and our substitute is practically teacher herself at the same time as teaching our class.Equation 1:
Log 50 - 2 Log 5 - Log 2Equation 2:
Log (x-3) = 1 + Log 4 - Log xEquation 3:
2-4a + 2 x 2-2a - 8 = 0Equation 4:
Without using calculator, find the value of A that makes x = e^12 / 1-2e^12 a solution of the equation:
ln x - ln (ax+1) = 12
I have attempted the first few on my own, how ever have not found the correct answer when checked against that of my calculator. They are listed below
Equation 1:
y=Log 50 - 2 Log 5 - Log 2
= 2 Log (50/5/2)
= 2 Log 5
Answer should be in Index form however I cannot make this into index formI'm sorry for such a long post, and don't expect to be given the questions directly, however any help would be appreciated, even if it just pointing me in the right direction or explaining how to complete them. I'm very grateful for any help you may provide
Thankyou
Jake
I am currently studying Math B in high school and am having an extremely hard time with my current assessment. If anyone could please help me with the equations listed below it would be very much appreciated as my current Math teacher is on long service leave, and our substitute is practically teacher herself at the same time as teaching our class.Equation 1:
Log 50 - 2 Log 5 - Log 2Equation 2:
Log (x-3) = 1 + Log 4 - Log xEquation 3:
2-4a + 2 x 2-2a - 8 = 0Equation 4:
Without using calculator, find the value of A that makes x = e^12 / 1-2e^12 a solution of the equation:
ln x - ln (ax+1) = 12
I have attempted the first few on my own, how ever have not found the correct answer when checked against that of my calculator. They are listed below
Equation 1:
y=Log 50 - 2 Log 5 - Log 2
= 2 Log (50/5/2)
= 2 Log 5
Answer should be in Index form however I cannot make this into index formI'm sorry for such a long post, and don't expect to be given the questions directly, however any help would be appreciated, even if it just pointing me in the right direction or explaining how to complete them. I'm very grateful for any help you may provide
Thankyou
Jake
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