Recent content by Julie323

okay, plugging in .2-x2 for x1 gives me 8.4x1-1.28=ma But where do I go from here?

Okay, I have tried messing around with it a little bit, but am not getting anywhere. I can't set x1=x2 can I since their k's are different? Are the forces of both sides equal?

I just figured part A out. I thought the problem was saying A was the equillibrium point, but it is actually the point when it is pushed down 16.5 cm, so the answer was 10.9+16.5 or 27.4 cm. Now part B is giving me trouble: How much time elapses between releasing the system at point and the...

okay, well I found the angular frequency to be 9.5 rad/s using sqrt{k/m}. I then found equations: x=16.5cos(9.5t), v=-9.5*16.5sin(9.5t), and a=-90.25*16.5cos(9.5t). Where do I go from here?

Homework Statement Two springs, each with unstretched length 0.200 m, but with different force constants k1 and k2, are attached to opposite ends of a block with mass m on a level, frictionless surface. The outer ends of the springs are now attached to two pins P1 and P2, 0.100 m from the...

Homework Statement A 1.70 kg, horizontal, uniform tray is attached to a vertical ideal spring of force constant 180N/m and a 295 g metal ball is in the tray. The spring is below the tray, so it can oscillate up-and-down. The tray is then pushed down 16.5 cm below its equilibrium point (call...

O okay. So the equation is 10-(4+2x2+2y2)? Which simplifies to 6-2r2. Integrating this using my previous limits gives me 9pi/4. Does that look right? Thanks so much!

z max would be 10 and z min would be 4. So I just integrate 4 r dr dtheta?

okay, so the equation I used also included the the portion of the paraboloid below the plane z=10? Do I need to subtract the portion below the plane? I don't know what to do with this kind of problem. I looked for an example like it in the book, but the only one was an even number so I do not...

Basically my question is how to set it up. What I have right now is r going from 0 to \sqrt{3} and theta from 0 to pi/2 For my equation I have tried -6 +2r^2 r dr d(theta) and 4 + 2r^2 r dr d(theta). These gave me answers of -9pi/4 and 21pi/4. These are both wrong. Does anyone see what I have...

Wow, something messed up with the symbols, but I meant 0 less than or equal to r less than or equal to square root of 3

Homework Statement Bounded by the paraboloid z = 4 + 2x2 + 2y2 and the plane z = 10 in the first octant. Homework Equations The Attempt at a Solution Plugging in 10 for z I got 3=x2+y2. From this, I set 0\leqr\leq3\sqrt{}. I wasn't sure what to do with the first octant, but I...

O right! I forgot to subtract the radius of the earth. I got both parts, thank you so much!

Homework Statement A. Suppose you are at the Earth's equator and observe a satellite passing directly overhead and moving from west to east in the sky. Exactly 15.0 hours later, you again observe this satellite to be directly overhead. How far above the Earth's surface is the satellite's...

Hey! So I figured out that I had the wrong equation a little earlier. I redid the problem, and it still came out wrong. I will go through what I did, and maybe you can tell me what is wrong: I started with the equation: mgh=Iw^2. I of rim=MR^2, R=.22m M=(.44m)(π)(2.5kg/m)=3.456kg I of...