Recent content by justindizzle

i'm hooped how do i solve for b then ? or can i square the entire equation into a2*b2*(1/4)

okay so we know the triangle is a right triangle, and that the hypotenuse has a length of 10cm. We're trying to find the max area. Pythagorean formula a^2 + b^2 = c^2 (C = hypotenuse) so according to what were given a^2 + b^2 = 10^ a^2 + b^2 = 100 we can rearrange this much into b^2...

i think you can actually use both formulas rearrange the pythagorean formula so that : b=10-a (hypotenuse was 10) so a^2 + b^2 = 10^2 then substitute it into the base height formula : = a(10-a) / 2 =10a - a^2 / 2 however when i solved for A and B i got 5*5/2 which = 12.5 but the answer is...

on second thought i don't think the pythagorean theorem would be relevant to the equation because the sides of the triangle are not changing and the derivative would imply that they do

Homework Statement The hypotenuse of a right triangle has length of 10cm. Determine its maximum possible area. c= 10cm Homework Equations a^2 + b^2 = c^2 ? b*h*(1/2) The Attempt at a Solution just drew out the triangle so far, confused as to where to go from here i assume ill...