Recent content by jxta

i think :- boys ways;-(7-1)=6! now there are 5 girls and 7 seats(in b/w boys) so there are P(7,5) number of ways, the girls can sit. p(7,5)=7!/(7-5)! i.e, total no. of ways= 6!*p(7,5) = 6!*7!/(7-5)! = 1814400 (but this ans is wrong). ans = 252 (in my book)

Circular Permutation?? if there are 7 boys and 5 girls, how many circular arrangements are possible if the ladies do not sit adjacent to each other.??