Recent content by K.S

On a horizontal air track, a glider of mass m carries a post shaped like an inverted "L". The post supports a small dense sphere, also of mass m, hanging just above the top of the glider on a cord of length L. The glider and sphere are initially at rest with the cord vertical. A constant...

Oh okay, that makes sense. Thanks!

Oh god, thanks Doc Al! You're a lifesaver. Okay I got it, and I did so by finding lim->inf ω_o/σ (1 - e(-σt)) = ω_o/σ Thanks Filip Larsen for the help too!

technician, thanks for the kind words! Yeah, maybe I'm just not used to rotational motion, my brain seems to spin along with the concept. Agreed, that's my main reason in joining the forum! cmb, Force is indeed a vector. However, in this expression, F = G(Ms)(Me)/r^2 = Me(v^2)/r , we're...

Filip Larsen, I did as you have suggested, and I obtained θ = ω_o/σ (1 - e(-σt)) , when I integrated ω from t=0 to t=t Now I have the variable t which i had attempted to find from the expression ω_o*e(-σt). Doc Al, I had wanted to find the time t when the wheel comes to rest - or as I had...

Oh, and you're welcome. :) I'm also a student, and have much to learn (Very likely from you all too!) - totally struggling with rotational physics sigh.

technician you are exactly right. Okay I think it was confusing I threw in kepler's third law here - what I have shown you is a prediction of that law. Earlier, I said that F = G(Ms)(Me)/r^2 = Me(v^2)/r, since the Earth can be seen as an object orbiting around the sun in a circular manner...

Oh my bad, take away the minus sign, In this case you can do so since both the centripetal force Me(v^2)/r and gravitational force G(Ms)(Me)/r^2 point towards the same direction - towards the center of the sun.

As a result of friction, the angular speed of a wheel changes with time according to dθ/dt = ω_o*e(-σt) where ω_o and σ are constants. The angular speed changes from 3.50 rad/s at t=0 to 2.00 rad/s at t=9.30s. (a) Use the information to determine σ and ω_o. Then determine (b) the...

Well you have period T = 365days = 3.1536E7 Try using Kepler's 3rd law in which F = -G(Ms)(Me)/r^2 = Me(v^2)/r , assuming it's a circular orbit - hence you can get rid of Me You know that v = 2(pi)(r)/T The rest of it should be pretty straightforward. :)