Recent content by kahunah

ok makes sense now thank you!

ok thanks. so specifically in relation to that question, they are talking about a 3-dimensional plane correct? (up) being the 3rd dimension or axis, (north) being the 2nd, and (east) for example being the 1st?

ok thank you for your advice. so if the B field points "up" do you think that if we had a x y z co ordinate system, up would refer to the positive z direction and north would be the positive y direction?

sorry it's definitely 0.0200 T. so if the B field is in the same direction as the velocity of the electron...why are they even asking the question and why is there an follow-up part b to the question? I really don't understand this question. like conceptually i get it but i don't think it's...

Homework Statement A magnetic field of 0.0200 T (up) is created in a region a. Find the initial magnetic force on an electron initially moved at 5.00 x 10^6 m/s [N] in the field b. What is the radius of the circular path? Make a sketch showing the path of the electron. Homework Equations...

so i went wrong in that i subtracted $$|\Delta \vec{v}| = \sqrt{(\Delta v_{x})^2 - (\Delta v_{y})^2}$$ instead of adding $$|\Delta \vec{v}| = \sqrt{(\Delta v_{x})^2 + (\Delta v_{y})^2}$$?

so what would i use to calculate the direction of the impulse and net force?

i know I'm just lost :S would it make sense to ensure that Fnetx ∆t = m(v2x – v1x) Fnety ∆t = m(v2y – v1y) yeild FnetTotal and that Fnettotal = ∆p/∆t?

Well there's a vector for velocity of the ball after its hit. 52 m/s w20n so that would tell me that the impulse needs a direction to it. Perhaps Fnet as well.

Homework Statement A baseball with a mass of 0.125 kg is moving horizontally at 32.0 m/s [E], when it is stuck by a bat for 0.00200 seconds. The velocity of the ball just after the collision is 52.0 m/s [W 20 N]. Homework Equations p = m Δv Fnet = ∆p/∆t there are also these...