Recent content by kaliprasad

we have $70^2 + 61^2 + c^2 = d^2$ or $4900 +3721 + c^2 -= d^2$ or $d^2-c^2 = 8621$ or ($d+c)(d-c) = 8621$ to solve the same you can put 8621 as product of 2 numbers (one case 8621 * 1$ equiate one to d +c and another to d- c and solve for c and d. by choosing all pair of numbers fot erach pair...

kindly infrom what you have tried and where you are facing problems

Of what ?

yes. 4b – a + 1 = 0 as there is no x term. you need to divide by x+1 and get the constant term (putting x = -1 shall do also) this shall give 2 equations and you need to solve and proceed further;