Recent content by KallKoll

Thank you so much!

Well, I set \sqrt{1+x} = u. Then I set u2 = 1 + x. But I don't understand how to get du from that or how that helps with getting rid of the x on top.

Yes that should be, thank you. How does the u^2 work?

Homework Statement Solve the equation dy/dx = x/(y^2√(1+x)) Homework Equations The Attempt at a Solution I separated them: y^2 dy = dx/√(1+x) I then integrated the dy side, I got (1/3)y^3 + C. I am stuck at integrating the dx side. Thanks in advance!