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A difficult 1D kinematics problem dealing with displacement and velocity
Distance/time = average velocity D/T = 1.31 t1 = time walking west t2 = time walking east d1 = distance walked west = 6.44 km = 6440 meters d2 = distance walked east T = t1 + t2 D = d1 - d2 t1 = distance/speed = 6440/2.54 = 2535.4 seconds t2 = d2/v2 = d2/0.475 so d2 =...- kathypoot
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- Forum: Introductory Physics Homework Help
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A difficult 1D kinematics problem dealing with displacement and velocity
In reaching her destination, a backpacker walks with an average velocity of 1.31 m/s, due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.54 m/s, due west, turns around, and hikes with an average velocity of 0.475 m/s, due east. How far east did...- kathypoot
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- 1d Displacement Kinematics Kinematics problem Velocity
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- Forum: Introductory Physics Homework Help