During nuclear fission a heavy nucleus of low binding energy splits into two middle mass nuclei with high binding energy ! From where does this energy suddenly come from ??
And why is the binding energy of heavy nuclei lesser than that of middle mass nuclei ??
Agreed . But c^2 is not just an unit conversion . It is also known "the specific energy" .
And I don't know what is "ρ" in the equation . Could you explain?
You actually mistook the whole derivation . v=E/Mc not E/mc ! 'M' and 'm' are different ... Go through the derivation once more . This derivation is not circular .
You can't do something like that because In E=mc^2 relation 'm' stands for the mass of light ! And in this equation v=E/Mc , 'M' stands for the mass of the cylinder ! Even if you put 'c' in the place of 'v' it won't become E=mc^2
Initial momentum or the momentum with which the light hits the cylinder will be equal to TOTAL ENERGY OF THE LIGHT / SPEED OF LIGHT (E/c).
Final momentum or the momentum with which the cylinder moves after colliding with light is just THE MASS OF THE CYLINDER * VELOCITY WITH WHICH IT MOVES...
Hey Hey ! Thats what I also meant ... Light matter is what you see everyday (ie) any object like a pencil , a bike or a car or even you and me , all are made up of light energy ! there are two types of energies (light energy and dark energy ) .
Oh ! I see ...The full derivation of this equation is given in this link ! http://www.drphysics.com/syllabus/energy/energy.html
It will answer your questions !
Also this derivation is made with respect to light .
you asked why this specific energy should be constant for substances right ...
@Dalespam : the reason why "e" is not directly proportional to "m^2" is because as i said earlier energy is mass and mass is energy . They need to be proportional .So "e" must be proportional to "m" and not "m^2" . If it is "m^2" that will mean mass and energy are different .