Recent content by keasterling

  1. K

    Solving for Period of SHM with Pendulum Hitting Peg

    Yeah, I meant little "g," not the "6.67 x10 to the blah blah blah." My bad. There's not really two periods, just that the one period was divided up into two sections. One half of the period was when the string length was just L. The next half of the period is for when the length is (L/2)...
  2. K

    Solving for Period of SHM with Pendulum Hitting Peg

    Try this one on for size: T=\pi\sqrt{\frac{L}{G}}+\pi\sqrt{\frac{L}{G}} T=\pi\sqrt{\frac{L}{G}}(1+\sqrt{}\frac{1}{2} How about that? Yay? Nay?
  3. K

    Solving for Period of SHM with Pendulum Hitting Peg

    Kind of. L is the overall length of the string (pendulum). The pendulum is swinging from left to right, and it hits a peg halfway through it's arc (positioned at the equilibrium). For the rest of the swing, the line has been shortened to L/2.
  4. K

    Solving for Period of SHM with Pendulum Hitting Peg

    Maybe if I post again, people will come. ?
  5. K

    Solving for Period of SHM with Pendulum Hitting Peg

    Yeah, I looked into part (a) a bit more, and I guess that it really isn't SHM mainly because the graph of position would not be sinusoidal. In other words, the amplitude of the graph would not be equal on either side because the pendulum wouldn't be moving equal distances from equilibrium on...
  6. K

    Solving for Period of SHM with Pendulum Hitting Peg

    1. A simple (massless string, point mass pendulum) pendulum swings down and hits a peg located at the equilibrium line halfway through the pendulum's swing. The pendulum's string has a length L when it's to the left of the peg, and length \frac{L}{2} after it hits the peg. (a)Is this simple...