Recent content by KennedYeti

Thanks for the help. I was making that waaaaaay to difficult for some reason.

n = the bright fringe , λ = wavelength, d = space between each line, Θ = angle that the order is seen. min = 400nm max = 700nm For first order on each end of the spectrum it would be sinθmin = nλ / d = θ = arcsin(n(400) / d) sinθmax = nλ / d = θ = arcsin(n(700) / d) second order would be...

I am assuming that it means that I have the first, second and third bright fringe and that the first and second will never overlap and the 2nd and 3rd will.

That is the problem in its entirety. I do not know how to determine the answer when so many variables are missing. I asked my instructor but they said. "What is the maximum angle that the light can be diffracted?" Super Confused!

Homework Statement "You're using a diffraction grating o view the 400 to 700 nm visible spectrum. Suppose you can see the spectrum through the third order. a) Show that the first and second order spectra never overlap regardless of grating spacing. b) show that the second and third order...