Recent content by KennyWRX
-
K
Ripple increase on higher load: at rectified output: 18Vac to 25.5Vdc
I don't think the regulator supply current by itself. Current is ultimately supplied by the transformer. If the transformer can only source 2A, the regulator won't be able deliver 2.5A. Your choices are a more capable transformer and/or more capacitance. Since you are trying to source more...- KennyWRX
- Post #5
- Forum: Electrical Engineering
-
K
Imaginary numbers outside of math
Phasors, Impedance, Complex Power... list goes on.- KennyWRX
- Post #9
- Forum: Electrical Engineering
-
K
Capacitors in rectifier circuits
I personally look at this in two different ways: First, capacitors have a low impedance to AC signals, and keeps decreasing as as freq increases, and a high impedance do DC signals. When you put the shunt capacitor in place, you create a current divider network that basically absorbs the AC...- KennyWRX
- Post #3
- Forum: Electrical Engineering
-
K
Energy directly proportional to frequency
Hz = 1/sec J*sec*Hz = (J*sec)/sec = J (Energy)- KennyWRX
- Post #2
- Forum: Introductory Physics Homework Help
-
K
Soundwave Intensity & Sound Level
L (dB) = 20*Log(P/Pref) = 10*Log(I/Iref) According to the units, you are given the pressure (50 uN/m^2 = 50 uPa). Sound Pressure Level is 20*Log(P/Pref) where Pref is 20uPa. You get around 8 dB. Sound Intensity = Sound Power / ***Area***. Now this 8 dB is just a ratio and is also equal to...- KennyWRX
- Post #2
- Forum: Introductory Physics Homework Help