Recent content by kenvin100

nvm i fixed it.apparently i think i broke the circuit when i added an extra input to pin 4..i just removed that wire and it worked..

yes i did that..its all on high..like on the +ve line..where pin 14 is connect to +5..and i have another wire connected to the power source..well the first led works and I tried another LED..so I really don't know what I am doing wrong

Okay, so I am trying to use the breadboard and I have a hard time with a three input AND gate. Guess I can do a schematic http://imageiso.com/out.php/i17298_3inputandgate.JPG So in my bread board, I have pins 1 and 2 as inputs..with pin 3 as a LED (output), and I have a jumper connecting...

ye the whole series is divided by n+1.. edit: nvm i solved it...

yes okay sorry [1 + 3 + 5 ...(2n-1)] / (n+1) - [(2n+1)/2] so 1 is the first term, and 2n-1 is the last term of the series. I don't know what the other part after the subtraction sign is... i hope this helped

Find the limit of the following series: lim (n-->infinity) 1 + 3 + 5 + 7 + ... (2n-1) / (n+1) - [(2n+1)/2] 3. From what I kno this is an arithmetic series, meaning I must use that arithmetic series formula. so its (first term + last term / 2 times the number of terms) n^2.. now...

u can always try to use a torrent to find pdf files of chem textbooks..but there are book stores that mite sell used old chem books..the content is great for a cheap price.. there rly isn't one stop shop for it though

i normally think of heterogeneous and homogeneous this way homogenous: think of it as 2 boys (same gender) heterogeneous: boy and girl (different genders) please don't laugh lol so salt is heterogeneous cause u see different particles (color wise w.e.) but salt, its all the same...