Recent content by Kerdo

I think I figured this out! 1) a = F/m => a = 2000/200 = 10m/s^2 A = Fs => A = mas => A = 200 * 10 * 400 = 800000J = 800kJ And it seems to be correct. For the second one I'm not sure how to use the air resistance.

For the second exercise I got: Ep = mgh, Ek = mv^2/2 Ep = Ek, mgh = mv^2/2 => gh = v^2/2 => v = sqrt(2gh) so v ~= 62,6m/s without the air resistance. How do I subtract the air resistance from there? Sorry, have been studying for preliminary exam for like 4 hours and it's all so confusing :D

Thanks for your reply! work = force * distance that means, 100% of potential energy is converted to work? And from there I can calculate the force and subtract the air resistance?

Thanks for your reply! 1) I was able to calculate the acceleration of the object which was (10 m/s^2). But didn't know how to go forward, I know that the object had kinetic energy, but there I need the velocity and for velocity I need time. 2) I haven't done any exercises with air resistance...

Hello! Would love a quick explanation of these two exercises :) 1. Homework Statement 1) Find objects acceleration, when mass is 200kg and it is being pulled on a horizontal plane with a force of 2000N. How much work is done on 400m road? 2) An object fell from 200m. How much of its energy...