Find the object's acceleration

Click For Summary

Homework Help Overview

The discussion revolves around two physics problems involving acceleration and energy conversion. The first problem concerns finding the acceleration of an object with a mass of 200 kg being pulled by a force of 2000 N on a horizontal plane, and calculating the work done over a distance of 400 m. The second problem involves an object falling from a height of 200 m, determining how much energy is converted to work against air resistance of 50 N, and finding the object's velocity upon impact with the ground, including a comparison of scenarios with and without air resistance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law to find acceleration and the relationship between work, force, and distance. There are questions about how to account for air resistance and how to calculate the velocity of the falling object. Some participants express confusion about the concepts of work and energy conversion.

Discussion Status

Several participants have provided insights and clarifications regarding the equations relevant to the problems. There is an ongoing exploration of how to incorporate air resistance into the calculations, and while some progress has been made in calculating acceleration and work, questions remain about the second problem's parameters and assumptions.

Contextual Notes

The discussion highlights the absence of the mass of the falling object in the second problem, which complicates the calculations related to forces acting on it. Participants are also navigating the implications of air resistance in their reasoning.

Kerdo
Messages
5
Reaction score
0
Hello!
Would love a quick explanation of these two exercises :)

1. Homework Statement

1) Find objects acceleration, when mass is 200kg and it is being pulled on a horizontal plane with a force of 2000N. How much work is done on 400m road?
2) An object fell from 200m. How much of its energy was converted to work, which deformed land when air resistance was 50N? What was the velocity of the object when it hit the ground? Which would have been the velocity if there was no air resistance?

Homework Equations


F = ma;
Ek = mv^2/2;

The Attempt at a Solution


1) Found the acceleration with the formula of Newton's second law, but couldn't go forward.
2) Don't get the air resistance part.
 
Physics news on Phys.org
Hello Kerdo

:welcome:
Kerdo said:
1) Found the acceleration with the formula of Newton's second law, but couldn't go forward.

What do you mean you couldn't go forward? If you're referring to work what is the relevant equation?

Kerdo said:
2) Don't get the air resistance part.

What have you tried for this so far?
 
  • Like
Likes   Reactions: PeroK
Kerdo said:
Hello!
Would love a quick explanation of these two exercises :)

1. Homework Statement

1) Find objects acceleration, when mass is 200kg and it is being pulled on a horizontal plane with a force of 2000N. How much work is done on 400m road?
2) An object fell from 200m. How much of its energy was converted to work, which deformed land when air resistance was 50N? What was the velocity of the object when it hit the ground? Which would have been the velocity if there was no air resistance?

Homework Equations


F = ma;
Ek = mv^2/2;

The Attempt at a Solution


1) Found the acceleration with the formula of Newton's second law, but couldn't go forward.
2) Don't get the air resistance part.

For 1) What do you know about work? What is work?
 
QuantumQuest said:
Hello Kerdo

:welcome:

What do you mean you couldn't go forward? If you're referring to work what is the relevant equation?
What have you tried for this so far?
Thanks for your reply!

1) I was able to calculate the acceleration of the object which was (10 m/s^2). But didn't know how to go forward, I know that the object had kinetic energy, but there I need the velocity and for velocity I need time.

2) I haven't done any exercises with air resistance, it seems like: object is falling with velocity x, so I have to calculate the force and subtract the air resistance?

PeroK said:
For 1) What do you know about work? What is work?
Thanks for your reply!

I know that work is the energy that gets lost when an object does something (am I correct?).
 
There is an equation relating work to force and something else that is listed in the question.

This equation will help with both questions.

Work = force * ?
 
Kerdo said:
I know that work is the energy that gets lost when an object does something (am I correct?).

No. Have you learned about work? Work expresses transfer of energy or conversion of energy from one form to another. There is an equation for work, as pointed out by CWatters, relating work, force and one more thing. Can you write it down?
 
CWatters said:
There is an equation relating work to force and something else that is listed in the question.

This equation will help with both questions.

Work = force * ?

Thanks for your reply!

work = force * distance

that means, 100% of potential energy is converted to work? And from there I can calculate the force and subtract the air resistance?
 
For the second exercise I got:

Ep = mgh, Ek = mv^2/2
Ep = Ek, mgh = mv^2/2 => gh = v^2/2 => v = sqrt(2gh)
so v ~= 62,6m/s without the air resistance.

How do I subtract the air resistance from there?

Sorry, have been studying for preliminary exam for like 4 hours and it's all so confusing :D
 
Kerdo said:
work = force * distance

The equation is Work = Force • Displacement • Cosine(theta) or ##W = F\cdot s\cdot \cos(\theta)## where ##\theta## is the angle between force and displacement. If the displacement takes place horizontally##^*## then this angle is ##0^{\circ}## and the equation becomes ##W = F\cdot s##. Can you finish the first question?

##^*##
and the force is collinear and in the same direction
 
Last edited:
  • #10
I think I figured this out!

1)
a = F/m => a = 2000/200 = 10m/s^2
A = Fs => A = mas => A = 200 * 10 * 400 = 800000J = 800kJ
And it seems to be correct.

For the second one I'm not sure how to use the air resistance.
 
  • #11
Kerdo said:
I think I figured this out!

1)
a = F/m => a = 2000/200 = 10m/s^2
A = Fs => A = mas => A = 200 * 10 * 400 = 800000J = 800kJ
And it seems to be correct.

Yes it is correct. There is no need to recalculate ##F##, it is given.

Kerdo said:
For the second one I'm not sure how to use the air resistance.

Note that the problem does not give the mass of the object, so you cannot calculate the force exerted on the object downwards. You're given only the air resistance. So what does this mean in terms of the method you will use?

EDIT: It is also a good idea to learn to use Latex. You can find help using the link which is right below your post editor on the left bottom ("?LaTeX / BBcode Guides").
 
  • #12
Kerdo said:
For the second one I'm not sure how to use the air resistance.

The air resistance is a force and you know the displacement.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
1
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
2K
Replies
18
Views
2K
Replies
1
Views
3K
Replies
1
Views
887