Recent content by kid

That is very helpful. My only question is how to find F(friction) at this point. Would it be the 41.16 number I got before or would that be Fnet?

Would V02 = V2 - 2aΔx be the equation of motion? Would that mean I'd have to find the velocity? Ok, so I drew a diagram. I calculated 41.16 and for Fk = μkmg, would I have to have a different kinetic value? Or like, treat the first value like a static value? I'm sorry if I'm totally wrong on...

I found that F= 41.16 N, and I believe that's right, but I don't know if it's relevant in this equation.

I guess to determine the Fk I would need uk (0.28) and Fn (9.8 m/s/s). So Fk=uk*Fn would be =2.744... is this sounding right so far or is it off? (thanks a lot for your help by the way.)

Homework Statement A 15kg crate slides across the floor. The coefficient of kinetic friction between the crate and the floor is 0.28. How much horizontal force is needed to accelerate the crate at 3.0 m/s/s? Homework Equations F=ma? The Attempt at a Solution F=? m= 15 kg u= 0.28 a= 3.0...