Recent content by killme22

here's my solution 1mi=5280 ft y=-1/2gt^2 -5280 = -1/2(32.2)t^2 t^2= -5280/(-16.1) t^2 = 327.95 t=18.11 secs...

my answer is 18.11 secs??

i think you're right boy .. here's my solution v^2 = Vo^2 - 2gy Vo=2.3m/s y=1.5+3.5 = 5m V=2.3^2 -2(9.8)(-5) V=10.16m/s downward .. :approve: