Recent content by kivit

ok I think I can do it now. thanks :) I'll let you know how it goes in a little bit!

so would i be right to start out defining g as uniformly continuous on R? then somehow using the denseness of Q to show that all the Qs are in R so g extends f? ... or am i not understanding what this means by extending?

Let f be a uniformly continuous function on Q... Prove that there is a continuous function g on R extending f (that is, g(x) = f(x), for all x∈Q I think I am supposed to somehow use the denseness of Q and the continuity of a function to prove this, but I am not quite sure where I should start...