Recent content by kmas55

The (1/2)(a - b) is a hint the 1st problem gives you. I misplaced it in the problem. The "neg p: for some ε' > 0 1/2(a - b), a > b + ε' ", should read " neg p: There is some ε' > 0 , so that a > b + ε'. And then the hint, define ε' = (1/2)(a - b). Sorry, it was late when I typed the original...

yes,, Yes, sorry, instead of "where ε > 0" I should have wrote "for all ε > 0".

Prove both by method of contrapositive. 1. If a ≤ b + ε, where ε > 0, then b > a. 2. If 0 ≤ a - b < ε, where ε > 0, then a = b. I'll start with problem 1.: p: If a ≤ b + ε, where ε > 0 q: b > a neg q: b < a neg p: for some ε' > 0 1/2(a - b), a > b + ε' define ε' = 1/2(a - b) I...