Recent content by koa

cauld somebody please check my answer hi, cauld somebody please check my answer i`m not sure if it`s right or wrong. Energy Equation: K1+U1+Wo=K2+U2,U1=U2=0 1/2IWo^2-FfD=1/2IWf^2+1/2MVf^2 , M=MASS, m= THE FRICTION COIFFICIENT I= 5/2MA^2 , V=AW, Ff=mGM , ACCELARATION=...

i think i got it i think i got it thanx i`ll post the solution after i finish it completely thank u

check this N=MG Fr=uN=uMG TORQUE=Fr.a(the radius)=I(ALPHA) BUT IN THE PROBLEM THEY DIDN`T GIVE US THE COIFICCIENT BETWEEN THE BALL AND THE TABLE??

hey tide , first of all i`d like to thank u for all ur help I can`t really see why :rolleyes:

i don`t know how to actually start i think first i have to get the energy equation which is K1+u1+others(the energy due to the friction)= k2+u2 we know that u1=u2=0 k1= 1/2 Iwo^2 k2= 1/2 Iw^2 +1/2 mv2 others= Fr. d(the distance the ball moved) second i think we can get the torque due...

A billiard ball of radius "a" is initially spinning about a horizontal axis with angular speed "w" and with zero forward speed. If the coefficient of sliding friction between the ball and the biliard table is "m", (A)find the distance the ball travels before slipping ceases to occur. (B) the...

i`m also working on this problem, and here`s what i end up with the intial potential energy= mg(L-Lcos(theta)) final energy will equal the sumtion of kinetic energy and potential= mg(l-rcos(alfa)) + .5mgv^2 i still don`t know how to get the velocity? i got one equation in twon unknowns...