Recent content by krete77

That's an outstanding response. It's a shame no one else could even come close to what you replied with. If there were some way of giving you a virtual high five, I would do it in a heartbeat. I will save this and in a few years down the road when I have some free time, I'll give this a...

I'm a body builder.. so I know a little about those things. They generally get very bad reviews and are never accurate. Waste of $$ imo. Back to the formula on hand, anyone else have any suggestions? I'm going to keep working it until I find someway to get a ballpark figure.

So is my approach a bad one? any idea on a new one? Should I come up with a multiplier for energy, and use that in conjunction with the number I get from work done?

Good point. Say I stayed in one spot. I lifted the log repetitively 150 times. Eliminating the x direction, would the formula now give me a ball park estimate?

You're right. I remember that. So, since there is no work being done as I move in the x direction, I could just take that out of the equation and get a ballpark figure, no?

Thanks for your reply. I know there isn't an simple way, I'm just trying to get a ballpark figure..just for self completeness really. Surely there must be some sort of work being done when I'm moving it since all muscles are contracted. I suppose that's more of a metabolic function rather then...

Hey guys, this isn't a homework question or anything. I ended up lugging a lot of wood the other day and decided I would try to figure out on my own how to find out how many calories I burned. I have a ton of data, but I'm just going to show you what I have done via this picture; hopefully...

ah simple mistake, thanks again.

i ran through my calculations again and got 11.5 still..here is what i have: -((-1)^2/2)-(-1)-(-(-2)^2/2)-(-2)+((-1)^2/2)+(-1)+((3)^2)/2)+(3)=11.5

Sweet, so I actually told you the correct answer, in which I was confusing myself upon. Haha, thanks for the confirmation though, it really helped. So, now, after all calculations, the final answer is: 11 1/2 could you confirm this please, this is an even number in my book and I cannot double...

using the integral recipe; x^mdx=x^m+1/m+1; so I am in the process of doing this for both. which would give me: -x^2/2 evaluated from -2 to -1; + 1x evaluated from -2 to -1 + x^2/2 evaluated from -1 to 3 + 1x evaluated from -1 to 3. Right? this is where i get lost

Ok, so then I integrate -(x+1) with the limits -2 to -1 + (x+1)dx with limits -1 to 3 . correct? from here, i need help integrating

When X is positive, I have no idea..i'm really confused by this stuff, which is why I'm just asking for a complete STEP BY STEP explanation..(in the original post). Would you mind? I have an example here of integral of 2x-4 , copied the notes from class, i want to compare the 2..

Ok...so next?

Yes, X=-1