Recent content by krimor09

thank you! i appreciate your patience

t^2 = (2.28 x 10^11/1.50 x 10^11)^3 t^2 = sqrt of 3.5 t = 1.87 years or about 2 years

Dm= 2.28 x 10^8m De= 1.50 x 10^11m Te= 365.2 days or 1 year Tm= ? (T/1 yr)^2 = (2.28 x 10^8m/1.50 x 10^11m)^3 (T^2/1yr) = 3.5 x 10^57) T^2 = sqrt of 3.5 x 10^57 = 5.9 x 10^28

okay, i tried this way out (t/365.2days)^2 = (2.28x10^11/1.50x10^11)^3 (T/365.2) = square root of 3.5 T^2/133371 = 1.87 multiply 133371 to both sides t^2 = the square root of 1.87 X 133371 T = 499

i just put up my work, i know that its wrong because my physics teacher said so, but I'm not sure what my major error is

Homework Statement Distance of Earth from Sun = 1.50 x 10^11m Period = 365.2 days Distance of Mars from Sun = 2.28 x 10^11km Period of Mars in Earth Years? Homework Equations (Ta/Tb)^2 = (Ra/Rb)^3 The Attempt at a Solution (365.2 days/Tm)^2 =(1.50 x 10^11m/2.28x10^14m)^3...