Recent content by kser

I also need help with this... is the equation you're talking about v = x/t?

nevermind! got it. thanks so much!

yup. I'm sorry i just don't get it. ugh. this whole mercury part it just not makin sense. so i find r in terms of n and get: r = 3.4/n^2 <--- is that even right? can't be because then I don't see how that would give me what I'm looking for. i am just not good at this stuf...

what do you mean by "dividing the two equations"? combine them? so a/3.40g = ((n^2r)/2))/n^2r ? I'm sorry, am i just looking into this way too much? I don't get what you're saying. because the way i see it. n is constant so when you half the radius, that also halves the acceleration right?

Homework Statement A laboratory centrifuge on Earth makes n rpm (rev/min) and produces an acceleration of 3.40 g at its outer end. Part A: What is the acceleration (in g's) at a point halfway out to the end? Part B: This centrifuge is now used in a space capsule on the planet Mercury...

So if the radius is half, and the equation for centripedal acceleration a = V^2/R, then the acceleration at the halfway point is double? Am I correct there with the equation and all? And I am also struggling with the mercury question. How would one go about to find the rpm in terms of n? I...