Ah, yes. A narrow-minded approach for me. I need this class to graduate so any help/verification is incredibly appreciated.
therefore... if they have the same acceleration
a = aA = aB
a = (FgA + FgB) / (mA+ mB)
= (17.9N + 29.4N) / ( 5kg)
= 9.4 m/s^2 North of East (to the right)
T = 5kg...
Homework Statement
http://img152.imageshack.us/img152/8286/imag0103l.jpg
*I'm aware my free body diagram is off and that normal force should be in the left quadrant.
Homework Equations
F=m*aThe Attempt at a Solution
Would I be correct in saying..
Fg of A = mg * sin (20)
= 2kg * 9.8 * sin...
Homework Statement
Block of mass mA = 2kg - lying on frictionless inclined plane with a slope of 20 degrees.
connected to mA via frictionless, massless pulley and massless cord... mB = 3kg
http://img152.imageshack.us/img152/8286/imag0103l.jpg
Homework Equations
F= Mass *...