Inclined Plane w/ Two Masses: F=ma+mb?

[ksm2288]

Homework Statement

Block of mass mA = 2kg - lying on frictionless inclined plane with a slope of 20 degrees.

connected to mA via frictionless, massless pulley and massless cord... mB = 3kg

http://img152.imageshack.us/img152/8286/imag0103l.jpg

Homework Equations

F= Mass * Acceleration

Acceleration = Mass / Force

The Attempt at a Solution

so far all I can get is the free body diagrams..
would this follow a = Fga + Fgb / ma + mb?

except I don't have force..

 

[azizlwl]

You have to draw 2 diagrams.
1. Forces exerted on mass#1
2. Forces exerted on mass#2

Make the unknown force as T.

 

[ksm2288]

I have drawn two diagrams? I attached a picture. So I'm just calculating the tension force?

 

[ehild]

Homework Statement

Block of mass mA = 2kg - lying on frictionless inclined plane with a slope of 20 degrees.

connected to mA via frictionless, massless pulley and massless cord... mB = 3kg

http://img152.imageshack.us/img152/8286/imag0103l.jpg

The normal force N is perpendicular to the slope. It is not vertical.
What do you call Fgma and Fgmb?
You drew only one force exerted to mb. You need to draw the force of gravity, too.
Remember that the tension, the magnitude of the force the cord exerts, is the same on both bodies.

Homework Equations

F= Mass * Acceleration

Acceleration = Mass / Force

The Attempt at a Solution

so far all I can get is the free body diagrams..
would this follow a = Fga + Fgb / ma + mb?

except I don't have force..

The equation is incorrect. You miss a few parentheses.
Explain, what Fga and Fgb are.


ehild