Recent content by lawsonfurther

Well, if we have done moving the charge Q to the other plate, the field between two plates should have been q/(E0L^2) as I found above. But after that, we need to remove another ΔQ again from the original plate. So shouldn't the field be altered during the process of transferring that amount of...

Well, I still don't get it. If I count only one side of the pill box, then E(L^2)=q/(epsilon) which means E=q/(E0L^2) with E0 being epsilon. Then if I use W=qEd, then the work I get will be q^2d/(E0L^2). Am I finding the right thing?

Okay. But in question (a) when those charges are on their way from one plate to the other plate which is initially neutral, the other plate shouldn't have any charge until those charges reach it. So in other words, shouldn't there be no electric field coming from the destination plate until the...

The field lines will point from the positively charged plate to the negatively charged plated and they will be perpendicular to the surface of the plates, if ignoring the edge effect.

So you were saying that the reason why the excess charges can't leave the surface is that they are still under control of the external electron cloud of the outermost atomic layer of the charged metal. Compared with the surface without being charged, the only thing that has changed is that the...

Homework Statement A capacitor has two square plates that are d apart. Each plate is L×L. The capacitor is initially uncharged. (a)Calculate the work required to move q of charge from one plate to the other. (b)Calculate the work required to move an additional q of charge from one plate to the...

My question is basically similar to a thread that was posted 12 years ago: https://www.physicsforums.com/threads/electrons-flying-off-a-conductor.119269/ I was glad to see that there was already a thread which asked my question in the forum. But when I read through all of the discussion, I don't...

Just as the title asks, I wonder if there can be any electric field inside an insulator when a point change is placed near it. If so, why?

Maybe you are too picky on my statement. What I mean is that the field vector of a positive test charge when it is placed at some point can be shown as the tangent vector (not sure I word it correctly) of the field line at that point if there exists a field line passing through that point. And...

To be honest, I have already played with this simulation program before I posted my question on this forum, and it is the diagram there that makes me think about whether or not there is an electric field line right between two positive charges. I think we can all agree on my last conclusion: not...

I think we can say for any point inside the field but not along the perpendicular bisector or the line connecting the charges, we can always find an electric field line that passes through that point. And the field lines are shown to us upon our request . But hold on. Suppose you are asked...

So electric field lines don't need to cover all the vicinity of two like charges (while they indeed cover when only a single charge is present). There are somewhere (to be exact, the perpendicular bisector and the line connecting the charges) where the direction of the acceleration of a test...

It is just part of my assumption. I said it before, if there isn't, please give me a logical explanation on the relationship between those two directions. I haven't been fully convinced by both opinions yet.

However, we are talking about the test charge which does not occupy any space, i.e. it is a point charge. So in the perspective of a test charge, there is no meaning of dense or sparse electric field lines. Only whether an electric field line passes through that charge and (if so) how a field...

I admit I can't come up with any idea to draw the field line on the line joining the charges, and I won't say the field line is discontinuous right between those charges. I think you're right. That is a good way to avoid any confusion.:smile: