Recent content by ldesai149

When I solve for C: From b), I have x(t) for t=3.0s is -18.0m x(3) = -18.0 = (3)2 - (1/3)(3)3 + C -18.0 = C But that doesn't seem right.

Alright, so I integrated v(t) to get x(t) = -1/3t3 + t2 + C. Input values of t=1,2,3,4 and found that at t=2.0s, the positive displacement is 1.33m, at t=3, it is 0m and at t=4, it is -5.3m. So, the maximum positive displacement is 1.33m at t=2.0s. Have I finally got it right?

Ok, so if I plug in different values for t in acceleration equation, the values are not constant... The only solution I can think of is to calculate x separately for each second? Also, am I correct in assuming that my answer for b) is still accurate since I calculated acceleration for the same...

The question doesn't say either way... I get the feeling I'm missing something but I don't know what.

Homework Statement The velocity of an object moving along the x-axis is given by Vx = (2.0t-t2)m/s. Initially (at t=0), the object was at the origin. a) Determine the object's acceleration at t=3.0s. b) Find the object's position at t=3.0s c) Calculate the object's maximum positive...

Homework Statement True/False: In the photoelectric effect, the cut-off (threshold) frequency depends on the intensity of incident light. Homework Equations hv = W + 1/2mv^2 v = W/h The Attempt at a Solution The threshold frequency depends on the wavelength of incident light...

Thank you! :D It was a question on an exam and I couldn't stop thinking about it..

Homework Statement True or False: If a pinhole camera casts on the screen an image of 40.0cm in size of an object situated at a distance of 40.0m from the camera, then the size of the object is 10.0m. Homework Equations M = hi/ho = di/do The Attempt at a Solution hi = 40.0cm do...