Recent content by lec0x

nevermind i figured it out you would do 59cos(20)=55.4 then you would do 55.4=ma 55.4=(5.2)a a=10.66

I just remember in class my teacher saying that x is sin and y is cosine even though it's usually the other way. so there is no μ and no friction, would the force applied be on the opposite side of Fgx so it would be Fapp-mgcosθ=ma 59-(5.2)(9.8)cos(20)=(5.8)a 11.11=5.8a a=1.92

Force With Angles! Homework Statement A child pulls a wagon with a force of 59 N by a handle making an angle of 20 degrees with the horizontal. If the wagon has a mass of 5.2 kg, to the nearest hundredth of a m/s2 what is the acceleration of the wagon? Homework Equations ƩF=ma The...