Recent content by leftdalltheway

Well the question says, find the TOTAL momentum. I'll ask my teacher about it. Thanks for your help!

okay, i think i got the ansewr. So i used vf^2 = vi^2 + 2a(yf-yi) vf2 = (8.49)^2 + 2 (-9.81(0-1.72)) vf = 10.29 so, resultant = ((10.29)^2 + (14.71)^2)^0.5 = 17.95 so this is the final velocity (?) then total momentum would be (2kg * 16.99m/s) + (2kg * 17. 95) = 69.88 is...

well the questions are: a) what is the distance of the throw b) what is the total momentum of the discus on landing? c) create a type 1 scatterplot to show the relationship between the projection angles, 0 degrees to 90 degrees, and the throw distance d) what is the optimal angle of...

hmm I'm sooo lost. initial speed is 16.99. direction and height? and how do i find the vertical and horizontal motion? i know that the initial vertical velocity is 8.49 (16.99sin30) and horizontal velocity is 14.71 (16.99cos30) what do i do after that? this is what I've done so...

Hmmm I don't understand how PE and KE comes into this... I practically know nothing about physics so...haha. Well i know that the initial momentum is 33.98 because i just multiplied the weight of the discus (2kg) times the velocity it was going (16.99m/s). But then, how do i figure out the...

Hi, I'm new here. I have a question with one problem and i was wondering if any of you could help me out! So um here's the problem.. A high school discus thrower rotates at an average angular acceleration of 895 degrees/sec^2 for 1.25 sec. The 2kg discus is realeased 0.87 meters away from...