Recent content by lela

Aaaah, that makes sense. I see now how it was wrong to think of it as only a reaction to the weight of AB, dang it seems so obvious now :doh: So since the structure here is stable I can assume the net forces on AB in the x and y directions are zero, and then use this together with all the other...

Ah, do you mean that I need to use the fact that the net torque must be zero to calculate the tension in the cable? If so, I understood this part. I am confused about how to calculate the force exerted by the pivot onto the pole AB (part b of the question) and why it is not parallel to the pole...

But I thought there was no torque about a pivot since the distance from the exerted force to the pivot is zero

Sorry, I don't understand. Am I supposed to take torques in consideration when looking for the force exerted by a pivot onto a pole? Thank you for the reply)

Thank you for the welcome and the reply! I highlighted the pole that I was talking about there in pink. Here are the free body diagrams, the top one is the one that I thought would be right and the bottom one is the one from my class notes (different vectors for the force from A/pivot), I drew...

Thank you!

I used to do homechooling and didn't really have mentors that would guide me through the classes , I would look for the study material for my exams on my own which led to me cutting corners when it came to studying/researching the physics part of my natural sciences exam, I focused on biology...

I thought that the force by the pivot A on the pole AB would be the reaction force to the x-component of the gravitational force on AB. This would mean that the force by the pivot would be parallel to the pole, but in my notes from class the force vector seems to be more along the bisector of...