Recent content by Leopold Stotch

hmm darn i was told that 5.4m was wrong... oh well, i appreciate the help, I'm going with the answers of either 2.25m or 3.15m, thank you very very much!

so that would mean 360 cm is 1 wavelength. If it is the third harmonic, then L=(3/2)(3.6m)=5.4m?

not sure exactly what to do next...

ok i get 1 as an answer for k... (inverse sin(.5))/30 = 1

i'm still not sure where to find the values for A and x. I'm sorry for being such a pain

is there any way to find the frequency(number value) just by knowing it's the third harmonic?

from my notes i believe that the wavelength of the string is 2/3 the total length

A string vibrates at its third-harmonic frequency. The amplitude at a point 30 cm from one end is half the maximum amplitude. How long is the string? i figured since the amplitude at point 30 cm is half the max amplitude, the amplitude must be at 60 cm. The third harmonic...