Recent content by lexpar

So, finally, 6sin2x-5sinx+1=0 over [0,2pi] when x = [.3398, 2.8, pi/4, 5pi/6,]

So, I learned from simplifying that the y coordinate of the points on the unit circle (which is describing the x-axis of my function) are 1/2 and 1/3. The y coordinate of 1/2 is described as 30 degrees and 150 degrees on the unit circle, or pi/6 and 5pi/6. To find the other two, I must find the...

I have absolutely no idea how to find that answer... Could you explain?

You'll have to forgive me for having no idea what I'm talking about... This entire section of trig was thrown at my class during this last week in preparation for exams. To clarify: sin(x)=1/3 x= .34 Can I go further than this in expressing it? Thanks again for your nearly instant response.

Homework Statement Find all solutions for 6sin2x-5sinx+1=0 over the interval [0, 2pi[The Attempt at a Solution 6sin2x-5sinx+1 (-3sin+1)(-2sin+1) 1/3 and 1/2 On unit circle, 1/2 is equal to pi/6 and 5pi/6... Not sure how to figure out 1/3! Any help would be much appreciated!

... I'm really not catching on to that one :C

Thank you all for the responses. You guys really run a quality forum here :D Can I tempt you guys with one more problem? This one wasn't assigned, I'm just curious. I'm looking for a step by step walkthru here if you guys can give it, since this one flies right over my head. Question...

Thanks, I got it :D Check out my last post, I edited it just for you <3 *ahem* So still having a bit of trouble with the second question. I get to: log3((x+4)(x+2)=1 log3(x2+6x+8)=1 apply the definition= x2+6x+8 = 3 But now I've got 2 x's! Where have I gone wrong??

In that case, what's the correct process? 31/5 is the correct answer, or so we were told. EDIT: Put a lot of thought into it. Read your earlier posts again: log2(5x-15)=4 logab=c then b=ac therefore 5x-15=24 x=31/5 Better? :D

Thanks all three of you for the ultra speedy reply :D Figured out the first: log25+log2(x-3)=4 log25(x-3)=4 log2(5x-15)=4 log25+log2x-log215=log216 log25+log2x=log231 5x=31 x=31/5! :D As for the second: log3(x+4)=log77-log3(x+2) log3((x+4)(x+2))= 1 (or maybe log33?) Where...

I'm new here. You already knew that. Thank you, you, for clicking on my thread in any case. So, I've got these two log problems. My math teacher gave them out as a challenge. The class is relatively new to logs, and I'm having trouble working with these longer questions (longer than "simplify...