Since the mass on the pulley is the one that made the block start moving. I think that the tension produced by that mass includes Force of gravity in the X and static friction of the block. That's why the equation I used is T=mg.
Homework Statement
(1) Firstly, the block as it rest at incline of 10 degrees and mass is added on the other side of pulley to overcome static friction (0.0063kg). The block weighs 0.8kg. Calculate the tension.
(2) The block is at same angle and mass but this time the block was lightly pushed...