Recent content by Line6spider

  1. L

    Calculating the distance the spring was compressed

    Would the PE equal the work in this case? I tried (1/2)kx2=8.61J Then I could say X=√((2*8.61)/600) right?
  2. L

    Calculating the distance the spring was compressed

    Well someone told me I could use 1/2k x^2= PE but it didn't really work out. Also, I tried using F=ma and Work is Force times Distance. So F=ma=W/d, but I am not sure where to go from there.
  3. L

    Calculating the distance the spring was compressed

    A 1300 g mass is on a horizontal surface with μk = 0.380, and is in contact with a compressed massless spring with a spring constant of 600 N/m. When the spring is released, it does 8.61 J of work on the mass while returning to its equilibrium position. Calculate the distance the spring was...