To find the second N, I have done this, but I do not feel as confident:
X-Analysis:
Fx - f = 0
Fsin30 - f = 0
Fsin30 = f
F = (f)/(sin30) [equation to plug in for F]
Y-Analysis:
N - W - Fy = 0
N - W - Fcos30 = 0
N - W - ((f)/sin30)•cos30
N - W - ((f)/tan30)
N - ((uN)/tan30) = W
N - ... at this...
OK, after coming back to the problem, I think I have figured it out:
So, X-analysis;
Fx - f = 0
Fcos30 - f = 0
Fcos30 = f
F = (u•N)/(cos30) [this is the equation for force that we can plug in]
Y-analysis;
N - W + Fsin30 = 0
N - W + ((u•N)/cos30)•sin30 = 0
N - W + (u•N)•tan30 = 0
N +...
Homework Statement
A student could either push or pull, at an angle of 30 degrees from the horizontal, a 40kg crate, where the coefficient of kinetic friction is .21. The crate is moved 18m. Calculate the minimum work for pushing and pulling.
Homework Equations
W=F•(change in)X•cos(angle in...